344. 反转字符串 发表于 2017-06-27 分类于 LeetCode题库 阅读次数: 编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。 不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。 示例 1: 12输入:["h","e","l","l","o"]输出:["o","l","l","e","h"] 示例 2: 12输入:["H","a","n","n","a","h"]输出:["h","a","n","n","a","H"] 代码实现: 双指针12345678910111213/** * @param {character[]} s * @return {void} Do not return anything, modify s in-place instead. */var reverseString = function (s) { let i = 0; let j = s.length - 1; while (i < j) { [s[i], s[j]] = [s[j], s[i]]; i++; j--; }};